How many grams of solid barium sulfate form when 30.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate? Aqueous sodium chloride forms also.

1.06g of BaSO₄ is produced

Explanation:

BaCl₂(aq) + Na₂SO₄(aq) ⇄ 2NaCl(aq) + BaSO₄(aq)

mole BaCl₂ = (0.16M × 0.030L) = 0.0048mole BaCl₂

mole Na₂SO₄ = (0.065M × 0.070L) = 0.00455mole Na₂SO₄

Amount of product BaSO₄ produce from each reagent

BaCl₂ = (0.0048 BaCl₂)  × ( 1 mol BaSO₄ / 1mol BaCl₂) × (233.3896g BaSO₄ / 1mol BaSO₄)

= 1.12g  BaSO₄

Na₂SO₄ = (0.00455 Na₂SO₄)  × ( 1 mol BaSO₄ / 1mol Na₂SO₄) × (233.3896g BaSO₄ / 1mol BaSO₄)

= 1.06g BaSO₄

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons