A student dissolves 14.g of benzoic acid C7H6O2 in 425.mL of a solvent with a density of 0.92 g/mL. The student notices that the volume of the solvent does not change when the benzoic acid dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.

Molarity of the solution is 0.26 M and molality of the solution is 0.28 m

Explanation:

Molar mass of benzoic acid = 122.12 g/mol

So, 14. g of benzoic acid = of benzoic acid = 0.11 mol of benzoic acid

We know, density is the ratio of mass to volume

So, mass of 425. mL of solvent  =

Molarity is defined as number of moles of solute dissolved in 1000 mL of solution

Here solute is benzoic acid and total volume of solution is 425. mL

So, molarity of solution =

Molality is defined as number of moles of solute dissolved in 1000 g of solvent

So, molality of solution =

the product of the pressure and volume is also constant

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.