6. How many moles of Cu(NO3)2 are in 25 ml of a 0.35 M solution of Cu(NO3)2? a) How many moles of NO3- are present in 25 ml of the above solution? b) What volume of this solution should be used to get 0.050 moles of Cu(NO3)2?

0.00875 moles Cu(NO3)2

a) 0.0175 moles NO3-

b) We should use 0.14L

Explanation:

Step 1: Data given

Volume = 25 mL = 0.025 L

Molarity of a Cu(NO3)2 solution = 0.35 M

Step 2: Calculate moles Cu(NO3)2

Moles Cu(NO3)2 = molarity * volume

Moles Cu(NO3)2 = 0.35 M * 0.025 L

Moles Cu(NO3)2 = 0.00875 moles

Step 3: Calculate moles NO3-

Cu(NO3)2 → Cu^2+ + 2NO3-

In 1 mol Cu(NO3)2 we have 2 moles NO3-

For 0.00875 moles Cu(NO3)2 we'll have 2*0.00875 = 0.0175 moles NO3-

Step 4: What volume of this solution should be used to get 0.050 moles of Cu(NO3)2?

Volume =  moles / molarity

Volume = 0.050 moles / 0.35 M

Volume = 0.14L

how about u try it first

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.