Consider the reaction: N2(g) + 2O2(g)2NO2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.90 moles of N2(g) react at standard conditions. S°system = J/K Submit Answer

Explanation:

It is known that standard entropies for is 191.6 J/mol K, = 205 J/mol K, and is 239.7 J/mol K at 298 K.

Therefore, we will calculate the value of from standard absolute entropies as follows.

                   = 2 mole of - 1 mole of + 2 mole of

                   =

                   = -122.2 J/K

The entropy change for 1.90 moles of reacting is as follows.

        = 1.90 moles of

                           = 232.18 J/K

Thus, we can conclude that the entropy change for the given system is 232.18 J/K.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons