What volume will 1.27 moles of helium gas occupy at stp

28.45L

Explanation:

1mole of a gas occupy 22.4L at stp. This implies that 1mole of He also occupy 22.4L at stp.

Now if 1mole of He occupied 22.4L at stp, then, 1.27mol will occupy = 1.27x22.4 = 28.45L

i'm pretty sure it is letter c.) car

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml