Chemistry, 03.03.2020 19:01 xxmattieboo7xx

How many moles of solute are contained in 200 milliliters of a 1 m solution?

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Answer from: lwattsstudent

0.2 moles of solute are in 200 mL

Explanation:

If we assume an aqueous solution, the solvent's density is 1g/mL

Solvent's volume = 200 mL

Solvent's density = Solvent's mass / Solvent's volume

Solvent's mass = solvent's density . solvent's volume → 200 mL . 1g/mL = 200 g

1 m means molality, we have 1 mol of solute in 1000 g of solvent, but in here the mass of solvent is 200 g. Let's make a rule of three:

1000 g of solvent have 1 mol of solute

Therefore, 200 g of solvent must have (200 .1) / 1000 = 0.2 moles

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

It conforms what ever surface its in.

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