What is the concentration of NOBr, if the concentration of NO was measured to be 0.89 M, Br2 was measured to be 0.562 M, and the equilibrium constant, K, is 1.3 × 10-2?

0.076M = [NOBr]

Explanation:

For the reaction:

2NO + Br₂ ⇄ 2 NOBr

The equilibirum constant, K, is defined as:

(1)

Replacing the concentrations and the equilibrium value in (1):

5.79x10⁻³ = [NOBr]²

0.076M = [NOBr]

I hope it helps!

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.