What salt is formed during the neutralization reaction between sulfuric acid left-parenthesis H subscript 2 S O subscript 4 right-parenthesis and lithium hydroxide (LiOH)?

Li₂SO₄ is the formed salt

Explanation:

We determine the reactants dissociations:

H₂SO₄ → 2H⁺ + SO₄⁻²

LiOH → Li⁺ + OH⁻

The 2H⁺ link the OH⁻ to form water, but there is one more H⁺, so we need another OH⁻ to finally produce 2 moles of H₂O

In conclussion to determine the lithium sulfate, which is the formed salt, Li will release 2 e⁻ as this equation shows:

2Li → 2Li⁺ + 2e⁻

Now the neutralization reaction is:

2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O

screening

explanation:

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.