Calculate the ratio of H+ ions to OH-ions at a pH = 7.
Find the concentration of Htions to OH-ions listed in
Table B of your Student Guide. Then divide the H+
concentration by the OH concentration. Record this
calculated ratio in Table A of your Student Guide.
Compare your approximated and calculated ratios of H+
ions to OH-ions at a pH = 7. Are they the same? Why or
why not? Record your comparison in Table A.
What is the concentration of H+ ions at a pH = 7?
mol/L
What is the concentration of OH-ions at a pH = 7?
mol/L
What is the ratio of Htions to OH-ions at a pH = 7?

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

56 moles of   lieter in chemistry

28528289 29823282 8298232 39858