What is the ratio of the cis and trans product formed in the reaction? (You can calculate this from GC/MS of your crude reaction. ~4.2 min (cis) and ~4.8 min (trans). Just divide the area of those peaks to get a ratio). What other byproduct do you see or expect to see in the GC/MS? You should discuss the purity of the recrystallized product based on NMR and how you know if your reaction was successful by NMR and GC/MS. Make sure to attach your GC/MS.

i just learnt this recently but i need to look through my notes again

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

answer seismograph;

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally