Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.50 L of a 0.130 M sucrose solution is allowed to react for 190 min .

Full Question:

The hydrolysis of sucrose C12H22O11 into glucose and fructose in acidic water has a rate constant of 1.8 x 10^-4 s^-2 at 25 C.

Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.50 L of a 0.130 M sucrose solution is allowed to react for 190 minutes.

96.96g

Explanation:

t = 190 x 60 = 11400 s (upon conversion to seconds)

k = 1.8 x 10^-4 s^-2

ln[A] −ln[A]o = −kt

ln[A] = -kt + ln[A]o

ln[A] = - ( 1.8 x 10^-4  * 11400) + ln (0.130)

ln[A] = - 2.052 - 2.04

[A] = 0.0167M

initial moles = 2.50 x 0.130 = 0.325

moles after 190 min = 0.0167 x 2.50 = 0.04175

moles hydrolyzed = 0.325 - 0.04175 = 0.28325

mass = 0.28325 x 342.30 g/mol = 96.96g

explanation:

i think option no d is the correct answer

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.