A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. What is the specific heat capacity of the alloy

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

fe 55.85 g/mol and h2o 18.02 g/mol.