A chemist prepares a solution of iron chloride by measuring out 0.10 g of FeCl2 into a 50. mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of anions in the chemist's solution.

The molarity of anions in the solution is 0.0316 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of iron (II) chloride = 0.10 g

Molar mass of iron (II) chloride = 126.75 g/mol

Volume of solution = 50 mL

Putting values in above equation, we get:

1 mole of iron (II) chloride produces 1 mole of ions and 2 moles of ions

So, concentration of chloride ions (anions) in the solution =

Hence, the molarity of anions in the solution is 0.0316 M

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.

thats how its supposed to be