An experiment requires 0.52 M NH3(aq). The stockroom manager estimates that 15 L of the base is needed. What volume of 15 M NH3(aq) will be used to prepare this amount of 0.52 M base

0.52 L of 15 M will be used to prepare this amount of 0.52 M base.

Explanation:

But on diluting the number of moles remain same and thus we can use molarity equation.

(to be prepared)

where,

=concentration of stock solution = 15 M

= volume of stock solution = ?

= concentration of solution to be prepared = 0.52 M

= volume of solution to be prepared = 15 L

Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base

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