A 2.35-g sample of an acid, H2X, requires 45.0 mL of a 0.500 M NaOH solution for complete reaction (removing both protons). The molar mass of the acid is: (Ignore significant figures for this problem.)

The molar mass of is 208.88 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaOH solution = 0.500 M

Volume of solution = 45.0 mL = 0.045 L     (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

The chemical equation for the reaction of NaOH and follows:

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of

So, 0.0225 moles of NaOH will react with = of

To calculate the number of moles, we use the equation:

Given mass of = 2.35 g

Moles of = 0.01125 moles

Putting values in above equation, we get:

Hence, the molar mass of is 208.88 g/mol

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