Brass rod is in contact thermally with a heat reservoir at 140 degrees C at one end and a heat reservoir at 50.1 degrees C at the other end. Compute the total change in the entropy (in calories/Kelvin) arising from the process of conducting 1,879 cal of heat through the rod.

5.18Cal/kel

Explanation:

Firstly, we calculate the temperature gradient across the brass rod. This can be calculated as 140 - 50.1 = 89.9 degrees Celsius. We can convert this to Kelvin as follows: 89.9 + 273.15 = 363.05K

The total change in entropy in Cal/kel is ΔS= q/T calculated as 1,879/363.05 = 5.18 Cal/kel

i think   the answer is c hope i'm right