50 POINTS + BRAINLIEST

PLZ HELP. This is due tomorrow! Please and thank you!!!

The answer to your question is below

Explanation:

1.-

Volume of water from ice = Volume of water plus melted ice - Volume of

                                               warm water.

                                           = 151 ml - 97 ml

                                           = 54 ml

2.-

mass of ice = (1)(54)

                   = 54 g

3.-

Change in temperature = 0.9°C - 44.6°C

                                       = -43.7°C

4.-

mass of warm water = (1)(97)

                                  = 97 g

5.-

Energy released = (97)(4.184)((43.7)

                            = 17735.6 Joules

                1000 J 1 kJ

               17735.6 J   x

                x = (17735.6 x 1) / 1000

               x = 17.7 kJ

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2