10.0 g of calcium carbonate was heated. The mass of calcium oxide left was 5.6 g. Calculate the mass of
carbon dioxide produced in the reaction.
CaCO3(s) + Cao(s) + CO2(g)

4.4g

Explanation:

Mass of CaCO3 = 10g

Mass of CaO = 5.6g

Mass of CO2 =?

Mass of CaCO3 = Mass of CaO + Mass of CO2

Mass of CO2 = Mass of CaCO3 — Mass of CaO

Mass of CO2 = 10 — 5.6

Mass of CO2 = 4.4g

4.4g

Explanation:

Calculate the molar mass of CaCO3

40+12+(16×3)

40+12+48

100 g/mol

Calculate the molar mass of CO2

12+(16×2)

12+32

44g/mol

100g of CaCO3=44g of CO2

10g of CaCO3=10×44/100

g of CO2=440/100

=4.4g of CO2

d. temperate deciduous forest

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )