For the reaction 2 HCl + Na2CO3 → 2 NaCl + H2O + CO2 8.0 moles of CO2 is collected at STP. What is the volume of CO2? 1. 57.6 L 2. 22.4 L 3. 0.0250 L 4. 2.80 L 5. 179 L 6. 0.357 L

Option 5. 179L

Explanation:

The reaction is:

2 HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂

The amount of collected CO₂ is 8 moles.

We apply the Ideal Gases Law at STP

STP are 1 atm of pressure and 273K of T°

P . V = n . R . T

1atm . V = 8 mol .0.082L.atm/mol.K . 273K

V = (8 mol .0.082L.atm/mol.K . 273K) / 1 atm = 179 L

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.