Calculate the mass of nitrogen dissolved at room temperature in an 89.0 LL home aquarium. Assume a total pressure of 1.0 atmatm and a mole fraction for nitrogen of 0.78.

Answer : The mass of nitrogen dissolved is, 79.4 grams

Explanation :

The Raoult's law for liquid phase is:

where,

= partial vapor pressure of nitrogen = ?

= total pressure = 1.0 atm

= mole fraction of nitrogen = 0.78

Now put all the given values in the above formula, we get:

Now we have to calculate the mass of nitrogen.

Using ideal gas equation:

where,

P = pressure of gas = 0.78 atm

V = volume of gas = 89.0 L

T = temperature of gas =

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas = ?

M = molar mass of nitrogen gas = 28 g/mole

Now put all the given values in the ideal gas equation, we get:

Therefore, the mass of nitrogen dissolved is, 79.4 grams