. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be released by an electron in a mercury atom to produce a photon of this light?

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be,

Explanation : Given,

Wavelength =

conversion used :

Formula used :

As,

So,

where,

= frequency

h = Planck's constant =

= wavelength =

c = speed of light =

Now put all the given values in the above formula, we get:

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be,

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b