6Li(s)+N2=2LiN
the mass of N2 needed to react with .536 moles of Li

Mass = 3.752 g

Explanation:

Given data:

Number of moles of Li = 0.536 mol

Mass of N₂ needed = ?

Solution:

Chemical equation:

2Li + N₂   →  2LiN

Now we we will compare the moles of Li and N₂.

                           Li           :        N₂

                            2          :          1

                          0.536    :         1/2×0.536 = 0.268 mol

Mass of N₂

Mass = number of moles × molar mass

Mass = 0.268 mol × 14 g/mol

Mass = 3.752 g