Chemistry, 10.03.2020 04:53 gabbym39077

A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of the gas decreases to 5.0 LL . Find the two constants kiki, the initial value of kk, and kfkf, the final value of kk, to verify whether the gas obeys Boyle’s law by entering the numerical values for kiki and kfkf in the space provided.

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Answer from: journeyhile5

The gas obeys Boyle’s law and the value of $k_i\&k_f$ both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = V_1=10.0 L

Initial pressure of the gas = P_1=4.0 atm

Final volume of the gas = V_2=5.0 L

Final pressure of the gas = P_2=8.0 atm

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

$P_1\propto \frac{1}{V_1}$

P_1V_1=k_i

$k_i=4.0 atm\times 10.0 L = 40.0 atm L$

$P_2\propto \frac{1}{V_2}$

P_V_2=k_f

$k_f=8.0 atm\times 5.0 L = 40.0 atm L$

k_i=k_f=40.0 atm L

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of $k_i\&k_f$ both are equal to 40.0 atm L.

Answer from: Quest

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

let g(n) be the amount of contaminants (in grams) that remained by the beginning of the nth hour. g is a sequence, what kind of sequence is it, arithmetic or geometric? then, write an explicit formula for the sequence, g(n)=

wanahton purified a portion of water with 900 grams of contaminants. each hour, a third of the contaminants was filtered out.

explanation:

Answer from: Quest

dynamic equilibrium is the answer.

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A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased...

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