8. Calculate the pH of 150.0 mL of H2O following the addition of 1.48 mL of 1.46 M NaOH. 12 You are correct. Your receipt no. is 158-1963 Help: Receipt Previous Tries 9. Calculate the pH of 250.0 mL of H2O following the addition of 1.49 mL of 0.99 M HCl. 2.23

12.15, 2.23

Explanation:

Using the dilution formula

C₁V₁ = C₂ V₂

where C₁ = 1.46 M

V₁  = 1.48 ml = 0.00148 L

C₂ = unknown

V₂ = 150 ml + 1.48ml = 151.48 ml = 0.15148L

1.46 M × 0.00148 L = C₂×0.15148L

C₂ = 0.0143 M

pOH = - log ( OH⁻) = - log ( 0.0143) = 1.85

pH + pOH = 14

pH = 14 - 1.85 = 12.15

b) using the same formula

C₁V₁ = C₂ V₂

C₁ = 0.99 M

V₁  = 1.49 ml = 0.00149 L

C₂ = unknown

V₂ = 250 ml + 1.49 ml = 251.49 ml = 0.25149 L

0.99 M × 0.00149 L = C₂ × 0.25149 L

C₂ = 0.00587

pH = - log ( H⁺) = - ( -2.23) = 2.23

h let me think

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.