If a 0.075gram sample of a weak acid is dissolved in a 30-mL aqueous solution and then 10.0mL of the solution is used in the titration, how many grams of the sample are used for the titration?Show all work.

The mass of the sample  used for the titration is 0.025 g

Explanation:

Given;

mass of the sample = 0.075 g

volume of aqueous solution = 30 mL

volume of solution used in the titration = 10 mL

If the volume of the solution used in titration is 10 mL, the mass of the sample used for the titration is;

M = CV;

Where;

m is the mass of the sample;

c is the concentration of the solution

v is the volume of the solution used

m = 2.5 x 10⁻³ x 10 = 2.5 x 10⁻² g = 0.025 g

Therefore, the mass of the sample  used for the titration is 0.025 g

fe 55.85 g/mol and h2o 18.02 g/mol.