An herbicide is found to contain only C, H, N, and Cl.

The complete combustion of a 100.0 mg sample of the herbicide in excess oxygen produces 83.16 mL of CO2 and 73.30 mL of H20 vapor at STP. A separate analysis shows that the sample also contains 16.44mg of Cl.

a. Determine the percent composition of the substance.
b. Calculate its empirical formula

b) mutualism

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a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

it would only be the stuff in module eight so you need to study all the lessons in that you also could check the flvs

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