An aqueous solution of hydrobromic acid is standardized by titration with a 0.164 M solution of calcium hydroxide. If 14.9 mL of base are required to neutralize 26.9 mL of the acid, what is the molarity of the hydrobromic acid solution

The molarity of hydrobromic acid is 0.182 M

Explanation:

Step 1: Data given

Molarity of Calcium hydroxide = 0.164 M

Volume of calcium hydroxide = 14.9 mL = 0.0149 L

Volume  of HBr = 26.9 mL = 0.0269 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: Calculate molarity of HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficient of HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficient of Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO BE DETERMINED

⇒Vb = the volume of HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity of hydrobromic acid is 0.182 M

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