A 2.50-kg steel gasoline can hold 20.0 L of gasoline when full.
What is the average density of the full gas can, taking into account the volume occupied by steel as well as by gasoline?

805 kg/m^3.

Explanation:

Okay, in the question above we are given the following parameters; the mass of steel gasoline= 2.50-kg, volume of gasoline it can hold= 20.0 L. Then we are asked to calculate the average density of the full can.

Recall that the formula for Calculating density = mass/ volume.

So, the total mass of the full can= mass of the steel can, m1 + mass of the gasoline, m2.

Although, we are not given but the density of gasoline = 0.68 g/cm^3 or 6.7 × 10^2 kg/m^3. (Note that you can use any of the value for density of gasoline just take note of the units, for instance one is in g/cm^3 and the other is in kg/m^3). For instance, if we take the one in g/cm^3 we have;

The mass of gasoline = 0.68 × (10^3 × 20).

Mass of gasoline = 13.6 ×10^3 g or 13.6 kg.

Since the mass in the question is given to us In kilograms we will be using the kg unit.

Therefore, the total mass of the full can= mass of the steel can, m1 + mass of the gasoline, m2.

===>2.50 + 13.6.

Then, going back to the formula for Calculating density, we have;

Average density= 2.50 + 13.6/ 20 × 10^3.

Average density = 805 kg/m^3.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.