What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)?Report your answer in scientific notation. Your answer should have two significant figures. Use −890.8kJmol for the molar heat of combustion of methane.

-2.9 X 10^4 kJ

Explanation:

First, calculate the number of moles of CH4 using a formula mass of 16.043gmol from the periodic table.

530g × 1.0 mol /16.043g = 33.036 mol

Next, calculate the total change in enthalpy.

ΔH = 33.036 mol × −890.8kJ/mol = −29,428kJ

The answer should have two significant figures, so round to −2.9 × 10^4 kJ.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.