A 0.3480 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 32.07 mL of sodium hydroxide solution are required to reach the equivalence point, what is the molarity of the sodium hydroxide solution

Recall the following terms which is,

KHP is Potassium hydrogen phthalate

NaOH is Sodium Hydroxide

NaKP is molar mass

H20 is water

Explanation:

KHP + NaOH = NaKP + H2O

moles of KHP = 0.3480g / 204.22 g·mol−1 = .001704

these will react with the same number of moles of NaOH according to the equation  

these are in 0.03207 L of solution

The  molarity of the NaOH solution = 0.001704 mol / 0.03207 L = 0.0531 M

the water takes no part in the reaction and the quantity can be ignored

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

the temperature of the gas, in k, not celsius.