In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is A. reduced by half. B. doubled. C. increased by half. D. left unchanged.

In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is also double.

Explanation:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Here P₁ is the initial pressure of a gas at temperature T₁ when its temperature change to T₂ its pressure also changes and this is change is directly related to each other.

Consider the following data:

Initial pressure = 13.0 atm

Initial temperature = 293 K

Final temperature = 586 K

Final pressure = ?

Now we will put the values in formula:

13.0 atm / 293 K = P₂/313 K

P₂ = 13.0 atm × 586 K / 293 K

P₂ = 7618 atm. K /293 K

P₂ = 26 atm

the answer is a. co2, this would be colder than the : )

explanation:

the temperature of the gas, in k, not celsius.