Part III. The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (aq) --> 3 I2(aq) 3 H2O(l) followed by reaction of the I2: I2(aq) 2 S2O32- --> 2 I-(aq) S4O62-(aq). What is the stoichiometric factor, that is the number of moles of Na2S2O3 reacting with one mole of KIO3

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

From Equation (2), the molar ratio of iodine to thiosulfate is

Combining the two ratios, we get

answer

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