Mercury (i) iodidne ->

Synthesis

Mercury(I) iodide can be prepared by directly reacting mercury and iodine.

Structure

In common with other Hg(I) (mercurous) compounds which contain linear X-Hg-Hg-X units, Hg2I2 contains linear IHg2I units with an Hg-Hg bond length of 272 pm (Hg-Hg in the metal is 300 pm) and an Hg-I bond length of 268 pm.[1] The overall coordination of each Hg atom is octahedral as it has in addition to the two nearest neighbours there are four other I atoms at 351 pm. [1]The compound is often formulated as Hg22+ 2I−.[2]

Historical Uses

Mercury(I) iodide was a commonly used as a drug in the 19th century, sometimes under the contemporary name of 'protiodide of mercury'. It was used to treat a wide range of conditions; everything from acne to kidney disease and in particular was the treatment of choice for syphilis. It was available over the counter at any drugstore in the world, the most common form being a concoction of protiodide, licorice, glycerin and marshmallow.[citation needed]

Taken orally, and in low doses, protiodide causes excessive salivation, fetid breath, spongy and bleeding gums and sore teeth. Excessive use or an overdose causes physical weakness, loss of teeth, hemolysing (destruction of the red blood cells) of the blood and necrosis of the bones and tissues of the body. Early signs of an overdose or excessive use are muscular tremors, chorea, and locomotor ataxia. Violent bloody vomiting and voiding also occur.

Protiodide is banned as a medication, even though it persisted in use as a quack remedy until the early 20th century.

Explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j