The reaction between potassium superoxide, KO₂, and CO₂,

is used as a source of O₂ and absorber of CO₂ in self-contained breathing equipment used by rescue workers.
How many moles of O₂ are produced when 0.300 mol of KO₂ reacts in this fashion?

Explanation:

1. Balanced chemcical reaction (given):

2. Mole ratio

Use the coefficients from the balanced chemical equation to form the mole ratio of O₂ to KO₂:

3. How many moles of O₂ are produced when 0.300 mol of KO₂ reacts in this fashion?

Mutiply 0.300 mol of KO₂ by the mole ratio:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied