Which noble-gas electron configuration is each of the following elements most likely to attain by graining or losing electrons? 1.S 2. Sr 3. Cl 4. Be

₁₆S = Ar

Sr = Kr

Cl = Ar

Be = He

Explanation:

The electronic configuration of sulfur is:

₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴

It has 6 electrons in valance shell. It can attain the stable electronic configuration which is the electronic configuration of noble gas element by gaining two more electrons thus it attain the electronic configuration of Ar₁₈.

The electronic configuration of strontium is:

₃₈Sr = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s²

It has 2 electrons in valance shell. It can attain the stable electronic configuration which is the electronic configuration of noble gas element by loosing two electrons thus it attain the electronic configuration of Krypton.

The electronic configuration of chlorine is:

₁₇Cl = 1s² 2s² 2p⁶ 3s² 3p⁵

It has 7 electrons in valance shell. It can attain the stable electronic configuration which is the electronic configuration of noble gas element by gaining one more electrons thus it attain the electronic configuration of Ar₁₈.

The electronic configuration of beryllium is:

₄Be =  1s² 2s²

It has 2 electrons in valance shell. It can attain the stable electronic configuration which is the electronic configuration of noble gas element by loosing two electrons thus it attain the electronic configuration of Helium.

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."