At a certain temperature, the equilibrium constant, K c , for this reaction is 53.3. H 2 ( g ) + I 2 ( g ) − ⇀ ↽ − 2 HI ( g ) K c = 53.3 At this temperature, 0.800 mol H 2 and 0.800 mol I 2 were placed in a 1.00 L container to react. What concentration of HI is present at equilibrium?

Concentration of HI is present at equilibrium is 1.26 M

Explanation:

Moles of   = 0.800 mole

Moles of   = 0.800 mole

Volume of solution = 1.00 L

Initial concentration of = 0.800 M

Initial concentration of = 0.800 M

The given balanced equilibrium reaction is,

Initial conc.         0.800     0.800             0

At eqm. conc.     (0.800-x) M   (0.800-x) M   (2x) M

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

By solving the term 'x', we get :

x = 0.63

Concentration of at equilibrium = 2 x =

Concentration of HI is present at equilibrium is 1.26 M

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.