Pleaasseee explain, really confused
in a laboratory experiment, pure lead metal reacted with excess sulfur to produce a lead sulfide compound. the following data was collected:

mass of empty evaporating dish: 25.000 g
mass of evaporating dish and lead metal: 26.927 g
mass of evaporating dish and lead sulfide: 27.485 g

solve for the empirical formula of the lead sulfide compound. be sure to show, or explain, all of your calculations.

We can get the mass of the lead metal by calculating the difference between the Mass of evaporating dish and lead metal and the mass of empty evaporating dish. The mass of lead metal is 1.9627 grams. The mass of sulfide is obtained by calculating the difference between Mass of evaporating dish and lead sulfide and the mass of evaporating dish and lead metal. The mass of sulfur added is 0.558 grams. We convert masses to moles. Lead is 0.0093 moles while sulfur is 0.017 moles. We divide each with the less amount between the two. Hence, lead is 1 an sulfur 1.83 or 2. The formula is PbS2 or lead (IV) sulfide. 

The answer to that would be magnesium

D.na is the answer hope this