At 500 °C, hydrogen iodide decomposes according to 2 HI ( g ) − ⇀ ↽ − H 2 ( g ) + I 2 ( g ) For HI ( g ) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [ H 2 ] = 0.335 M , [ I 2 ] = 0.335 M , and [ HI ] = 2.83 M . If an additional 1.00 mol of HI ( g ) is introduced into the reaction vessel, what are the equilibrium concentrations after the new equilibrium has been reached?

[HI] = 3.61 mol·L⁻¹; [H₂] = [I₂] = 0.446 mol·L⁻¹  

Explanation:

1. Calculate Keq

                     H₂   +      I₂    ⇌ 2HI

E/mol·L⁻¹:    0.335    0.335    2.83

2. Set up an ICE table.

Step 3. Calculate the equilibrium concentrations

[HI] = (3.83 - 2x) mol·L⁻¹ = (3.83 - 0.2223) mol·L⁻¹ = 3.61 mol·L⁻¹

[H₂] = [I₂] = (0.335 + x) mol·L⁻¹ = (0.335 + 0.1111) =  0.446 mol·L⁻¹  

Check:

Close enough.

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .