1. Determine the empirical formula of a compound
containing 59.0% Na and 41.0% O by mass.
(a) NaO
(b) Na2O
(c) NaO2
(d) Na2O3
(e) none of these

NaO

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number .

Given data:

Percentage of sodium = 59.0%

Percentage of oxygen = 41%

Empirical formula = ?

Solution:

Number of gram atoms of Na = 59.0 / 23 = 2.6

Number of gram atoms of O = 41 / 16 = 2.6

Atomic ratio:

            Na                      :            O            

           2.6/2.6               :          2.6/2.6

              1                       :              1      

Na  : O = 1:1

Empirical formula is NaO.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

1 is the answer to this problem