Calcium oxide reacts with water to produce calcium hydroxide and 65.2 kJ of heat in the following reaction. CaO (s) + H2O (l) → Ca(OH)2 (s) ΔH = - 65.2 kJ How much heat is released when 100.0 g of calcium oxide reacts with excess water?

116.43 kJ of heat is released when 100.0 g of calcium oxide reacts with excess water.

Explanation:

, ΔH = -65.2 kJ

Mass of calcium oxide = 100.0 g

Moles of calcium oxide =

According to reaction, 1 mole of calcium oxide on reaction with water gives off  65.2 kilo Joules of heat. Then 1.7857 moles of calcium oxide will give:

116.43 kJ of heat is released when 100.0 g of calcium oxide reacts with excess water.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

i think   the answer is c hope i'm right