A gas has a volume of 4.54 L at 1.65 atm and 75.0°C. At what pressure would the volume of the gas be increased to 5.33 L if the
temperature is increased to 103°C?

The new pressure is 1,52 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

75°C=273+75=348K  ; 103°C=273+103=376K

(P1xV1)/T1=(P2xV2)/T2

(1,65atm x4,54L)/348K= (P2x 5,33L)/376K

0,0215 atmxL/K=(P2x 5,33L)/376K

P2=(0,0215 atmxL/K x 376K)/5,33l= 1,52 atm

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