A sample of an ideal gas at 1.00 atm and a volume of 1.82 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 15.0 atm , what was the volume of the sample? Assume that the temperature was held constant.

The answer to your question is Volume = 0.12 L

Explanation:

- Data

Pressure 1 = 1 atm

Volume 1 = 1.82 L

Pressure 2 = 15 atm

Volume 2 = ?

Temperature = constant

- Formula

- To solve this problem use the Boyle's law

            P1V1 = P2V2

- Solve for V2

            V2 = P1V1 / P2

- Substitution

             V2 = (1)(1.82) / 15

- Simplification

             V2 = 1.82 / 15

- Result

             V2 = 0.12 L

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explanation:

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