The reaction of pyridine, C5H5N, with methyl chloride, CH3I, to yield C6H8NI produces the following rate data.[C5H5N](M)[CH3I](M)Rate(M/s)1. 00 X 10-41.00 X 10-47.5 X 10-72.00 X 10-42.00 X 10-43.0 X 10-62.00 X 10-44.00 X 10-46.1 X 10-6Write the rate law for this process. Calculate the rate constant. Predict the initial rate for initial concentrations of [C5H5N] = 1.5 X 10-4 M and [CH3I] = 6.1 X 10-5 M

Explanation:

[C5H5N](M)  [CH3I](M)       Rate(M/s)

1.00 X 10-4   1.00 X 10-4    7.5 X 10-7

2.00 X 10-4  2.00 X 10-4    3.0 X 10-6

2.00 X 10-4   4.00 X 10-4   6.1 X 10-6

Doubling the concentration of CH3I causes the rate to increase by a factor of 2. The reaction is first order with respect to CH3I.

Doubling both concentrations increases the rate of reaction by a factor of 4. In addition with the order of CH3I, we can conclude that the reaction is also first order with respect to C5H5N.

Rate Law;

Rate = k [C5H5N] [CH3I]

Rate constant;

Picking experiment 1;

Rate = k [C5H5N] [CH3I]

7.5 X 10-7 = 1.00 X 10-4 * 1.00 X 10-4 * k

k = 7.5 X 10-7 / 1.00 x 10-8

k = 7.5 x 10^1 = 75

Predict the initial rate for initial concentrations of [C5H5N] = 1.5 X 10-4 M and [CH3I] = 6.1 X 10-5 M

Rate = k [C5H5N] [CH3I]

Rate = 75 * 1.5 X 10-4 * 6.1 X 10-5

Rate = 686.25 x 10-9

Rate = 6.8625 x 10-7M/s

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explanation:

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the atomic mass is the bottom number on the element.

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