Sample of an ideal gas at 1.00 atm and a volume of 1.09 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 45.0 atm , what was the volume of the sample

The answer to your question is 0.024 L

Explanation:

Data

Pressure 1 = 1 atm

Volume 1 = 1.09 L

Pressure 2 = 45 atm

Volume 2 = ?

Process

1.- To solve this problem use the Boyle's law

               P1V1 = P2V2

- Solve for V2

              V2 = P1V1 / P2

- Substitution

              V2 = (1)(1.09) / 45

- Simplification

              V2 = 1.09 / 45

- Result

             V2 = 0.024 L or 24.2 mL

idk

explanation: