The following reaction was carried out in a 2.50 LL reaction vessel at 1100 KK: C(s)+H2O(g)⇌CO(g)+H2(g)C(s)+H2O(g)⇌ CO(g)+H2(g) If during the course of the reaction, the vessel is found to contain 10.0 molmol of CC, 16.0 molmol of H2OH2O, 3.30 molmol of COCO, and 7.00 molmol of H2H2, what is the reaction quotient QQQ? Enter the reaction quotient

Q = 0.144

Explanation:

reaction quotient:

∴ [C(s)] = 10.0 mol/2.50 L = 4 M

∴ [H2O(g)] = 16.0 mol/2.50 L = 6.4 M

∴ [CO(g)] = 3.30 mol/2.50 L = 1.32 M

∴ [H2(g)] = 7.00 mol/2.50 L = 2.8 M

⇒ Q = (2.8 M)(1.32 M) / (6.4 M)(4 M)

⇒ Q = 0.144

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

the answer is 0.8m.

by: nicholas