What pressure is required to compress 189.0 liters of air at 1.00 atm into a cylinder whose volume is 28.0 liters

6.75atm

Explanation:

The following data were obtained from the question:

V1 = 189L

P1 = 1atm

V2 = 28L

P2 =?

Using Boyle's law equation P1V1 = P2V2 the pressure required to compress the gas can be obtained as follows:

P1V1 = P2V2

1 x 189 = P2 x 28

Divide both side by 28

P2 = 189/28

P2 = 6.75atm

Therefore, the pressure require to compress the gas is 6.75atm

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