Write the expression for the equilibrium constant Keq for the reaction below: 2CO(g) + O2(g) ⇔ 2CO2(g) a. [CO2] / [CO] [O2] b. [CO]2 / [CO2]2 [O2] c. [CO2]2 / [CO]2 [O2] d. [CO]2 [O2] / [CO2]2 Group of answer choices

The answer is NOT A. [CO2] / [CO] [O2]

just took the test and I chose A. The test did not tell me the correct answer. Sorry.

Explanation: NOT, I REPEAT NOT: A. [CO2] / [CO] [O2]

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.