An iron bar weighed 565 g. After the bar had been standing in moist air for a month, exactly one-eighth of the iron turned to rust (Fe2O3). Calculate the final mass of the iron bar and rust.

Final mass of Iron bar will be 621.105 g.

Mass of rust = 126.730 g

Explanation:

Exactly one- eighth of the Iron turns to rust. That means, the mass of Iron  that under go the process of rusting() = 565 × = 70.625 g

So, the mass of pure Iron after rusting will be = 565 - 70.625 = 494.375 g

Now the reaction of rusting as follows,

   2Fe + →

Now, molecular weight of Iron = 55.84 g

So, moles of Iron undergoes the reaction is = = 1.26 mol

Molecular weight of = 159.68 g

Here 2 moles of Iron undergoes the reaction to produce 2 moles of Iron oxide.

Hence, 1.26 mol of Iron will produce 1.26 mole of Iron oxide.

Mass of = = 126.730 g

∴Mass of rust = 126.730 g

∴ Final mass of Iron bar = ( 494.375 + 126.730) = 621.105 g

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?

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