When a 120g sample of aluminum absorbs 9612 J of energy its temperature increases from 298K to 388K. Find the specific heat of the aluminum.

Specific heat of Aluminium is 0.89 g/J

Explanation:

Step  1 :

Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.

Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference

Step  2 :

It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.

Temperature Difference = 388 K - 298 K = 90 K

Step  3:

Specific Heat = (Energy Absorbed) ÷ (Mass of the substance * Temperature Difference)

Specific Heat = 9612 ÷  (120 * 90) = 0.89 grams / Joule

Step  4:

Specific heat of Aluminium is 0.89 g/J

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error