Determine the [H3O+] in a 0.265 M HClO solution. The Ka of HClO is 2.9 × 10-8.

a. 1.3 × 10-6 M
b. 7.7 × 10-9 M
c. 1.1 × 10-10 M
d. 8.8 × 10-5 M
e. 4.9 × 10-4 M

8.8X10^-5 M

Explanation:

HClO is a weak acid that ionizes by the equation:

HClO + H2O <--> H3O+ + ClO-

Ka = [H3O+][ClO-]/[HClO] = 2.9X10^-8

Let [H3O+] = [ClO-] = x. [HClO] = 0.265 -x.

Because Ka is small, assume x << 0.265 and can be ignored. Then,

Ka = 2.9X10^-8 = x^2 / 0.265

x = [H3O+] = 8.8X10^-5 M

they both have a y in them

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.